Answer :
s - the length of a side
P - the perimeter (which equals four times the length of a side)
[tex]s_1=2.5 \ m \\ P_1=4s_1=4 \times 2.5 \ m=10 \ m \\ \\ \hbox{each side is doubled in length} \Rightarrow s_2=2 \times 2.5 \ m=5 \ m \\ P_2=4 s_2=4 \times 5 \ m= 20 \ m \\ \\ \frac{P_2}{P_1}=\frac{20 \ m}{10 \ m}=2[/tex]
If each side is doubled in length, the perimeter is two times the original perimeter.
P - the perimeter (which equals four times the length of a side)
[tex]s_1=2.5 \ m \\ P_1=4s_1=4 \times 2.5 \ m=10 \ m \\ \\ \hbox{each side is doubled in length} \Rightarrow s_2=2 \times 2.5 \ m=5 \ m \\ P_2=4 s_2=4 \times 5 \ m= 20 \ m \\ \\ \frac{P_2}{P_1}=\frac{20 \ m}{10 \ m}=2[/tex]
If each side is doubled in length, the perimeter is two times the original perimeter.
s - the length of a side
P - the perimeter (which equals four times the length of a side)
s_1=2.5 \ m \\ P_1=4s_1=4 \times 2.5 \ m=10 \ m \\ \\ \hbox{each side is doubled in length} \Rightarrow s_2=2 \times 2.5 \ m=5 \ m \\ P_2=4 s_2=4 \times 5 \ m= 20 \ m \\ \\ \frac{P_2}{P_1}=\frac{20 \ m}{10 \ m}=2
If each side is doubled in length, the perimeter is two times the original perimeter.