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Janet is three years older than her sister Julie. Janet's brother is eight years younger than their sister Julie. the sum of all of their ages is 55 years.



Answer :

Assume Julie is x years old

(x+3)+x+(x-8)=55                   Julie is 20 years old

3x-5=55                                 Janet is 23 years old

3x=60                                     brother is 12 years old

x=20

Let us assume age of Julie to be x years this implies age of janet is (x + 3) years and age of Janet's brother is (x - 8) in this way we will solve for x and find out everyone's age.

How we are assuming and constructing ages from the given question and forming them into mathematical expressions ?

here we have taken x years for the person having least age for our convenience.Her sister is 3 years older than her so her age addition to 3 years.Her elder brother is 8 years younger than her sister so her sister's age less to 8 years.

in the given question sum of their ages is 55

So,

        [ x + (x + 3) + (x - 8) ] = 55

         3x - 5 = 55

         3x = 60

          x = 20

So, Julie's age is 20 years

     Janet's age is 20 +3 = 23 years

      Janet's brother's age is  = 20 - 8 = 12 years.

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