Answer :

[tex]f(-2)=-3\cdot(-2)+2=6+2=8\\ f(-1)=-3\cdot(-1)+2=3+2=5\\ f(0)=-3\cdot0+2=0+2=2\\ f(1)=-3\cdot1+2=-3+2=-1\\ f(2)=-3\cdot2+2=-6+2=-4\\\\ \text{The range: }y\in\{-4,-1,2,5,8\} [/tex]

Other Questions