Answer :
If that is 6-3(log2n)=0 then how you would go about solving it is by looking at log2n like x. In this case, for 6-3x=0, x would have to =2. So log2n has to =2. If log2n=2 and we assume that the base is 10 (because if there is no written base on a log then it is 10) then we need to rewrite the log to exponential form. Rewritten it's 10^2=2n. 100=2n, divide both sides by 2 and you get n=50.
[tex]6 - 3log2n = 0[/tex]
[tex]-3log2n = -6[/tex]
[tex]log2n = 2[/tex]
[tex] 10^{2} = 2n[/tex]
[tex]100 = 2n[/tex]
[tex]n = 50[/tex]
[tex]-3log2n = -6[/tex]
[tex]log2n = 2[/tex]
[tex] 10^{2} = 2n[/tex]
[tex]100 = 2n[/tex]
[tex]n = 50[/tex]
