Answer :

Sinx = opps/hyp = 1/2

2^2 = 1^2 + x^2
x = sqrt(3) = adj

Cosx = adj/hyp = sqrt(3)/2

Value of cos x = ( √3 / 2) for 0° < x° < 90°.

What are trigonometric function?

" Trigonometric function is defined as the relation between sides and angles of a right angled triangle."

Formula used

(Hypotenuse)² = ( Opposite side)² + ( Adjacent side)²

sinθ = (Opposite side) / (Hypotenuse)

cosθ = (Adjacent side) / (Hypotenuse)

According to the question,

Given,

0° < x° < 90°

sin x = 1 / 2

Substitute the value in the formula we get,

Opposite side = 1

Hypotenuse = 2

(2)² = (1 )² + (Adjacent side)²

⇒(Adjacent side)² = 4 - 1

⇒ Adjacent side = ±√3

0° < x° < 90°

cos x >0

Therefore,

cos x = √3 / 2

Hence, value of cos x = ( √3 / 2) for 0° < x° < 90°.

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