Answer :
[tex](x+a)(x+a)=x^2+2ax+a^2\\\\
2a=10 \wedge a^2=24\\
a=5 \wedge (a=\sqrt{24} \vee a=-\sqrt{24})\\
a=5 \wedge (a=2\sqrt{6} \vee a=-2\sqrt{6})[/tex]
The above is contradiction, so there are no such values of 'a'.
The above is contradiction, so there are no such values of 'a'.
