Answer :
The standard form of the equation of a circle:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
r - radius
[tex](x+5)^2+(y-7)^2=36 \\ \Downarrow \\ r^2=36 \ and \ r>0 \\ r=6[/tex]
The answer is A. 6.
[tex](x-h)^2+(y-k)^2=r^2[/tex]
r - radius
[tex](x+5)^2+(y-7)^2=36 \\ \Downarrow \\ r^2=36 \ and \ r>0 \\ r=6[/tex]
The answer is A. 6.