Answer :
Anything to the power of 0 is one.
Therefore we have:
(1)(y^-7z)
Which simplifies to:
y^-7z
Therefore we have:
(1)(y^-7z)
Which simplifies to:
y^-7z
Answer:
[tex]\frac{1}{y^{7z}}[/tex]
Step-by-step explanation:
Given the expression:
[tex]-(14)^0 \cdot y^{-7z}[/tex]
We know that:
[tex]a^0 =1[/tex]
[tex]a^{-1} = \frac{1}{a}[/tex]
then;
[tex]1 \cdot y^{-7z}[/tex]
⇒[tex]y^{-7z}[/tex]
⇒[tex]\frac{1}{y^{7z}}[/tex]
Therefore, the simplified form of [tex]-(14)^0 \cdot y^{-7z}[/tex] is, [tex]\frac{1}{y^{7z}}[/tex].
