Answer :
[tex]D:x-4>0 \wedge x+3>0 \wedge x>0\\
D:x>4 \wedge x>-3 \wedge x>0\\
D:x>4\\\\
\log(x-4)+\log(x+3)=2\log x\\
\log(x-4)(x+3)=\log x^2\\
(x-4)(x+3)=x^2\\
x^2+3x-4x-12=x^2\\
-x=12\\
x=-12\\
-12\not\in D\\
\Downarrow\\
\boxed{x\in\emptyset}[/tex]
