Answer:
C. 400 J
Explanation:
In physics, work is defined as
[tex]W=F \times \Delta d[/tex]
Where [tex]W[/tex] is the word done, [tex]F[/tex] is the force that move the object and [tex]\Delta d[/tex] is the change of the position of the object.
In this case, we have
[tex]F= 100 \ N[/tex]
[tex]\Delta d= 6m - 2m = 4m[/tex], remember that the difference refers to the actual subtraction between the final point and the initial point of the object.
Replacing these values, we have
[tex]W= 100 \ N \times 4m\\W=400 \ Joules[/tex]
Therefore, the right answer is C. The work done is 400 Joules
