Answer :
This problem requires the knowledge of the area of a rectangle.
The area of any rectangle is Area=Length•Width.
Since the maximum area is 3003.04 cm² and the width is 16 cm, you the area and length into this equation.
3003.04=16•Width
To solve for your width you must divide 3003.04 by 16.
3003.04÷16=187.69
So the greatest possible width of Carmen's painting is 187.69.
The area of any rectangle is Area=Length•Width.
Since the maximum area is 3003.04 cm² and the width is 16 cm, you the area and length into this equation.
3003.04=16•Width
To solve for your width you must divide 3003.04 by 16.
3003.04÷16=187.69
So the greatest possible width of Carmen's painting is 187.69.
