Answer :
[tex]x-\ number\\\\\
5(x-4)>\frac{4x}{6}\ \ \ | multiply\ by\ 6\\\\
30(x-4)>4x\\\\
30x-120>4x\ \ \ \ | subtract\ 4x\\\\
26x-120>0\ \ \ | add\ 120\\\\
26x>120\ \ \ | divide\ by\ 26\\\\
x>\frac{120}{26}\\\\
x>4\frac{8}{13}[/tex]
5 times (5 times) the differnce (-) a number(x) and 4(4) is greater than (>) the quotient (/) 4 times the nmber (4x) and 6 (6)
5(x-4)>4x/6
5x-20>4x/6
treat > as an equals for nnow
multiply both sides by 6
30x-120>4x
divide both sides by 2
15x-60>2x
add 60 to both sides
15x>2x+60
subtract 2x from both sides
13x>60
divide both sdie sby 13
x>60/13
the smalles tnumber is the next number bigger then 60/13
5(x-4)>4x/6
5x-20>4x/6
treat > as an equals for nnow
multiply both sides by 6
30x-120>4x
divide both sides by 2
15x-60>2x
add 60 to both sides
15x>2x+60
subtract 2x from both sides
13x>60
divide both sdie sby 13
x>60/13
the smalles tnumber is the next number bigger then 60/13