Answer :
[tex] \left \{ {{y=6x-11} \atop {-2x-3y=-7}} \right. \ \ \ | substitute\ first\ equation\ into \ the\ second\\\\
-2x-3(6x-11)=-7\\\\
-2x-18x+33=-7\\\\
-20x+33=-7\ \ \ | subtract\ 33\\\\
-20x=-40\ \ \ | divide\ by\ -20\\\\
x=2\\\\
y=6x-11=6*2-11=12-11=1[/tex]
just subsitute 6x-11 for y in the second equation
-2x-3(6x-11)=-7
-2x-18x+33=-7
-20x+33=7
subtract 33 from both sides
-20x=-40
multiply -1
20x=40
dividede by 20
x=2
then subsitute
y=6x-11
y=6(2)-11
y=12-11
y=1
x=2
y=1
-2x-3(6x-11)=-7
-2x-18x+33=-7
-20x+33=7
subtract 33 from both sides
-20x=-40
multiply -1
20x=40
dividede by 20
x=2
then subsitute
y=6x-11
y=6(2)-11
y=12-11
y=1
x=2
y=1