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Marisa can buy 3 oranges for 1.35 dollars ,four oranges for $1.80 or five oranges for $2.25 per second by 10 oranges for a price that fits this pattern or a bag of 10 oranges for four dollars and 25 Cents Which Way cost less for 10 oranges explain



Answer :

HolmesNWatson
3 oranges= $1.35, so one orange cost $0.45
4 oranges= $1.80, one orange cost $0.45
5 oranges= $2.25, one orange cost $0.45
If one orange cost $0.45, then ten cost $4.50 ($0.45*10)

If you were to buy ten oranges are $4.25, this would make each orange $0.425 ($0.43 rounded).

This means that if you were to buy ten oranges, it would be cheaper to buy ten for $4.25, instead of buying two lots of 5 for $2.25 each.

Hope this helps :) 
akbusiness987

Answer:

10 for $4.25 has a better value than 2 bunches of 5 for $2.25 each.

Step-by-step explanation:

3 oranges = $1.35

[tex]\frac{1}{3} :\frac{y}{1.35}[/tex]

y × 3 = 1 × 1.35

3y = 1.35

3y ÷ 3 = 1.35 ÷ 3

y = $0.45

4 oranges = $1.80

[tex]\frac{1}{4}: \frac{y}{1.8}[/tex]

y × 4 = 1 × 1.8

4y = 1.8

4y ÷ 4 = 1.8 ÷ 4

y = $0.45

5 oranges = $2.25

[tex]\frac{1}{5} :\frac{y}{2.25}[/tex]

y × 5 = 1 × 2.25

5y = 2.25

5y ÷ 5 = 2.25 ÷ 5

y = $0.45

[tex]\frac{1}{10} :\frac{0.45}{y}[/tex]

y × 1 = 0.45 × 10

y = $4.50

[tex]\frac{1}{10} :\frac{y}{4.25}[/tex]

y × 10 = 1 × 4.25

10y = 4.25

10y ÷ 10 = 4.25 ÷ 10

y = 0.425

$0.425 ≈ $0.43

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