Answer :
3 oranges= $1.35, so one orange cost $0.45
4 oranges= $1.80, one orange cost $0.45
5 oranges= $2.25, one orange cost $0.45
If one orange cost $0.45, then ten cost $4.50 ($0.45*10)
If you were to buy ten oranges are $4.25, this would make each orange $0.425 ($0.43 rounded).
This means that if you were to buy ten oranges, it would be cheaper to buy ten for $4.25, instead of buying two lots of 5 for $2.25 each.
Hope this helps :)
4 oranges= $1.80, one orange cost $0.45
5 oranges= $2.25, one orange cost $0.45
If one orange cost $0.45, then ten cost $4.50 ($0.45*10)
If you were to buy ten oranges are $4.25, this would make each orange $0.425 ($0.43 rounded).
This means that if you were to buy ten oranges, it would be cheaper to buy ten for $4.25, instead of buying two lots of 5 for $2.25 each.
Hope this helps :)
Answer:
10 for $4.25 has a better value than 2 bunches of 5 for $2.25 each.
Step-by-step explanation:
3 oranges = $1.35
[tex]\frac{1}{3} :\frac{y}{1.35}[/tex]
y × 3 = 1 × 1.35
3y = 1.35
3y ÷ 3 = 1.35 ÷ 3
y = $0.45
4 oranges = $1.80
[tex]\frac{1}{4}: \frac{y}{1.8}[/tex]
y × 4 = 1 × 1.8
4y = 1.8
4y ÷ 4 = 1.8 ÷ 4
y = $0.45
5 oranges = $2.25
[tex]\frac{1}{5} :\frac{y}{2.25}[/tex]
y × 5 = 1 × 2.25
5y = 2.25
5y ÷ 5 = 2.25 ÷ 5
y = $0.45
[tex]\frac{1}{10} :\frac{0.45}{y}[/tex]
y × 1 = 0.45 × 10
y = $4.50
[tex]\frac{1}{10} :\frac{y}{4.25}[/tex]
y × 10 = 1 × 4.25
10y = 4.25
10y ÷ 10 = 4.25 ÷ 10
y = 0.425
$0.425 ≈ $0.43
