Answer: 1040 feet.
Step-by-step explanation:
We know that , Perimeter of a rectangle = 2 (length +width)
As per given , we have
Length of football ground = [tex]53\dfrac{1}{3}\text{yards}=\dfrac{53\times3+1}{3}\text{yards}=\dfrac{160}{3}\text{ yards}[/tex]
Width = 120 yards
Since, the football ground is rectangle in shape.
Then , Perimeter of the ground = [tex]2(\dfrac{160}{3}+120)[/tex] yards
[tex]=2(\dfrac{160+3(120)}{3})[/tex] yards
=[tex]2(\dfrac{160+360}{3})[/tex]yards
[tex]=2(\dfrac{520}{3})[/tex] yards
[tex]=\dfrac{1040}{3}[/tex] yards
Also, 1 yard =3 feet
i.e. Perimeter = [tex]\dfrac{1040}{3}\times3=1040[/tex] feet
Hence, the required perimeter is