Answer :
[tex] \left \{ {{3x-5y=-6\ \ | *3} \atop {-9x-5y=18}} \right. \\\\ \left \{ {{9x-15y=-18} \atop {-9x-5y=18}} \right. \\+----\\add\ both\ equations\\\\
-20y=0\ \ \ | divide\ by \ -20\\\\
y=0\\\\
3x-5y=-6\ \ \ \ add\ 5y\\\\
3x=-6+5y\ \ \ | divide\ by\ 3\\\\
x=\frac{-6+5y}{3}=\frac{-6+0}{3}=-2\\\\ x=-2\\ y=0[/tex]
we can eliminate the y term by multiplying by -1 and adding
-9x-5y=18
multiply -1
9x+5y=-18
add
3x-5y=-6
+ 9x+5y=-18
12x+0y=-24
12x=-24
divide by 12
x=-2
subsitute
3(-2)-5y=-6
-6-5y=-6
add 6 to both sides
-5y=0
y=0
x=-2
y=0
-9x-5y=18
multiply -1
9x+5y=-18
add
3x-5y=-6
+ 9x+5y=-18
12x+0y=-24
12x=-24
divide by 12
x=-2
subsitute
3(-2)-5y=-6
-6-5y=-6
add 6 to both sides
-5y=0
y=0
x=-2
y=0