danielleg
danielleg
18-02-2015
Mathematics
Answered
(x^-2/y^-3)^2 / (y/x^2)^-3
Answer :
yanmega
yanmega
18-02-2015
[tex] \frac{ (\frac{ x^{-2} }{ y^{-3} })^2 }{ (\frac{y}{ x^{2} })^{-3} } = \frac{ (\frac{ x^{-4} }{ y^{-6} }) }{ (\frac{ y^{-3} }{ x^{-6} }) }= \frac{ x^{-4}* x^{-6} }{ y^{-3}* y^{-6} } = \frac{ x^{-10} }{ y^{-9} } [/tex]
Answer Link
Panoyin
Panoyin
18-02-2015
(x-²/ y-³)²
=
(x-²/y-³)(x-²/y-³)
= (
y/ x²)(y/ x²)
=
(y²/ x^4)
=
y² · x^4
=
1
(y/ x²)-³ (y/x²)(y/x²) (x²/y³)(x²/y³) (x^4/ y^6) x^4 · y^6 y^4
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