Answer :
I'll show you two ways.
By substitution:
[tex]x+3y=11\\ 2x-y=1\\\\ x=11-3y\\ 2x-y=1\\\\ 2(11-3y)-y=1\\ 22-6y-y=1\\ -7y=-21\\ y=3\\\\ x=11-3\cdot3\\ x=11-9\\ x=2\\\\ \boxed{(x,y)=\left(2,3\right)}[/tex]
By elimination:
[tex]x+3y=11\\ 2x-y=1|\cdot 3\\\\ x+3y=11\\ \underline{6x-3y=3}\\ 7x=14\\ x=2\\\\ 2+3y=11\\ 3y=9\\ y=3\\\\ \boxed{(x,y)=\left(2,3\right)}[/tex]
By substitution:
[tex]x+3y=11\\ 2x-y=1\\\\ x=11-3y\\ 2x-y=1\\\\ 2(11-3y)-y=1\\ 22-6y-y=1\\ -7y=-21\\ y=3\\\\ x=11-3\cdot3\\ x=11-9\\ x=2\\\\ \boxed{(x,y)=\left(2,3\right)}[/tex]
By elimination:
[tex]x+3y=11\\ 2x-y=1|\cdot 3\\\\ x+3y=11\\ \underline{6x-3y=3}\\ 7x=14\\ x=2\\\\ 2+3y=11\\ 3y=9\\ y=3\\\\ \boxed{(x,y)=\left(2,3\right)}[/tex]