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Write the balanced equation for the reaction of aqueous Pb(ClO3)2 with aqueous NaI.



Answer :

Scryt
[tex]Pb(ClO_3)_{2(aq)}+2NaI_{(aq)}=PbI_{2(s)}+2NaClO_{3(aq)}[/tex]
kenmyna
 The  balanced  equation for the  reaction  of aqueous Pb(ClO3)2  with aqueous NaI   is as below

Pb(ClO3)2(aq)  + 2NaI(aq)  → PbI2(s) +  2 NaClO3(aq)

    Explanation

 from the equation  above   1mole  of lead(ii) chlorate Pb(ClO3)2   react   with    2 moles  of sodium  iodide  to form   1 moles  of lead(ii)  iodide( PbI2)  and  2  moles  of sodium chlorate NaClO3.  

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