The standard form of this equation is
[tex]y=\frac{1}{3}x+2[/tex]
The slope of two parallel lines i the same, so the slope of the line we're looking for is also [tex]\frac{1}{3}[/tex]
Since the line passes through [tex](-3,4)[/tex], the equation is:
[tex](y-4)=\frac{1}{3}(x+3)[/tex]
[tex]\boxed{y=\frac{1}{3}x+5}[/tex]
