The cost of the milk is [tex]\fbox{\$\,0.41{\text{ a gallon}}}[/tex] in 1950s.
Further explanation:
The price of milk in 2013 was around [tex]\$3.28[/tex] a gallon.
And it is given that this was eight times as much as one can would have probably paid for a gallon of milk in the 1950s.
It is given that the price of milk in 2013 is [tex]\$3.28[/tex] a gallon.
Assume the price of milk in 1950 be [tex]\$x[/tex] a gallon.
Now, given that 8 times of [tex]x[/tex] is the price of milk in 2013.
Therefore, [tex]8x[/tex] is the price of milk in 2013 and also [tex]\$3.28[/tex] is the price of milk in 2013.
Equating [tex]8x[/tex] and [tex]\$3.28[/tex] equal as both are the price of milk in 2013 as,
[tex]\begin{aligned}8x&=3.28\\x&=\frac{{3.28}}{8}\\x&=0.41\\\end{aligned}[/tex]
Here, x is the price of milk in 1950.
Therefore, the cost of the milk is [tex]\fbox{\$\,0.41{\text{ a gallon}}}[/tex] in 1950s.
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Answer details:
Grade: Middle school
Subject: Mathematics
Chapter: Linear equations in one variable
Keywords: Cost, gallon, milk, linear equation in one variable, polynomials, variables, real numbers, degree of polynomials, equations, expressions, coefficients, zero polynomial, constants, integers, roots of polynomials.
