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what mass of sodium chloride is produced when chlorine gas reacts with 0.29 grams of sodium iodide? working on stoichiometry and need help!



Answer :

UFGators
CI2 + 2Nal ---> 2NalCI + I2
Nal = 149.9 g/mol.
NaCI = 58.5 g/mol
2 mol Nal makes 2 mol NaCI
0.29 g Nal x ( 1 mol / 149.9 g) = 0.0019 mol NaCI
00.19 mol NaCI x ( 58.5 g / 1 mol ) 0.11 g NaCI ( 2 sig figs)

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