[tex]-3x+9y=18 \\ \\
\hbox{x-intercept - y=0:} \\
-3x+9 \times 0=18 \\
-3x=18 \ \ \ |\div (-3) \\
x=-6 \\ \\
\hbox{y-intercept - x=0:} \\
-3 \times 0+9y=18 \\
9y=18 \ \ \ |\div 9 \\
y=2[/tex]
The x-intercept is -6 and the y-intercept is 2. The answer is A.