Anonym
Anonym
28-02-2015
Mathematics
Answered
If (x-y)^2-(x+y)^2=-20, determine the value of xy
Answer :
alina274
alina274
28-02-2015
(x-y)^2-(x+y)^2= -20
x^2-2xy+y^2-(x^2 + 2xy + y^2)= -20
x^2
-2xy
+y^2 -x^2
-2xy
-y^2
= -20
-4xy= -20
xy = -20/ -4
xy = 5
Answer Link
konrad509
konrad509
28-02-2015
[tex](x-y)^2-(x+y)^2=-20\\ x^2-2xy+y^2-(x^2+2xy+y^2)=-20\\ x^2-2xy+y^2-x^2-2xy-y^2=-20\\ -4xy=-20\\ xy=5[/tex]
Answer Link
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