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An electronics company used a pipe that was 100 ft long and had a radius of 10 ft. Inside the pipe was a smaller cylindrical tube, for wires, that had a radius of 2 ft and was as long as the pipe. The remaining space in the pipe, outside the tube, was filled with liquid foam.What was the volume of the foam inside the pipe? Use 3.14 to approximate pi.

Please help An electronics company used a pipe that was 100 ft long and had a radius of 10 ft Inside the pipe was a smaller cylindrical tube for wires that had class=


Answer :

V(foam)=V(pipe)-V(tube)
V(foam)=π r²(pipe) h - πr²(tube) h
V(foam)=π 10² 100 -π 2² 100
V(f)=π 100(10² - 2²)
V(f)= π 100(100-4)
V(f)=π 100 96
V(f)=30144