Answer :
The correct answer is n²+3.
Explanation:
We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.
Since these are different, this is not linear.
We now find the second differences:
5-3=2; 7-5=2; 9-7=2.
Since these are the same, this sequence is quadratic.
We use (1/2a)n², where a is the second difference:
(1/2*2)n²=1n².
We now use the term number of each term for n:
4 is the 1st term; 1*1²=1.
7 is the 2nd term; 1*2²=4.
12 is the 3rd term; 1*3²=9.
19 is the 4th term; 1*4²=16.
28 is the 5th term: 1*5²=25.
Now we find the difference between the actual terms of the sequence and the numbers we just found:
4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.
Since this is constant, the sequence is in the form (1/2a)n²+d;
in our case, 1n²+d, and since d=3, 1n²+3.
Explanation:
We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.
Since these are different, this is not linear.
We now find the second differences:
5-3=2; 7-5=2; 9-7=2.
Since these are the same, this sequence is quadratic.
We use (1/2a)n², where a is the second difference:
(1/2*2)n²=1n².
We now use the term number of each term for n:
4 is the 1st term; 1*1²=1.
7 is the 2nd term; 1*2²=4.
12 is the 3rd term; 1*3²=9.
19 is the 4th term; 1*4²=16.
28 is the 5th term: 1*5²=25.
Now we find the difference between the actual terms of the sequence and the numbers we just found:
4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.
Since this is constant, the sequence is in the form (1/2a)n²+d;
in our case, 1n²+d, and since d=3, 1n²+3.
Answer:
The nth term in the given sequence will be:
[tex]n^2+3[/tex]
Step-by-step explanation:
We are given a sequence as:
4,7,12,19,28,....
Let [tex]a_n[/tex] represents the nth term in the sequence.
i.e. [tex]a_1=4\\\\a_2=7\\\\a_3=12\\\\a_4=19\\\\a_5=28[/tex]
i.e. these terms could also be written as:
[tex]a_1=(1)^2+3\\\\a_2=(2)^2+3=7\\\\a_3=(3)^2+3=12\\\\a_4=(4)^2+3=19\\\\a_5=(5)^2+3=28\\\\.\\.\\.\\.\\.\\.\\.a_n=(n)^2+3=n^2+3[/tex]
Hence the nth term in the given sequence will be:
[tex]n^2+3[/tex]
