Answer :
x = 4 y = - 3
Substitute x for 4 and y for - 3
x² - 4y
2
4² - 4 *(- 3)
2
16 - ( - 12 )
2
16 + 12
2
28 = 14
2
Solution: 14
Substitute x for 4 and y for - 3
x² - 4y
2
4² - 4 *(- 3)
2
16 - ( - 12 )
2
16 + 12
2
28 = 14
2
Solution: 14
[tex] \frac{x^2-4y}{2} = \frac{4^2-4*(-3)}{2} = \frac{16+12}{2} = \frac{28}{2} =14[/tex]