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Which of the following dimensions form a trapezoid with an area of 4 1/8 square units?

A- h= 1 1/2, b1 = 6, b2 = 3 1/2

B- h=1 1/2, b1 = 2, b2 = 3 1/2

C- h= 3, b1 = 2, b2 = 3 1/2

D- h= 1 1/2, b1 = 2, b2 = 7



Answer :

AL2006

The area of a trapezoid is  (¹/₂) (height) (base-1 + base-2)

A). Area = (¹/₂) (1¹/₂) (6 + 3¹/₂) = (¹/₂) (³/₂) (¹⁹/₂) = ⁵⁷/₈ = 7¹/₈

B). Area = (¹/₂) (1¹/₂) (2 + 3¹/₂) = (¹/₂) (³/₂) (¹¹/₂) = ³³/₈ = 4¹/₈  <===

C). Area = (¹/₂) (3) (2 + 3¹/₂) = (¹/₂) (⁶/₂) (¹¹/₂) = ⁶⁶/₈ = 8¹/₄

D). Area = (¹/₂) (1¹/₂) (2 + 7) = (¹/₂) (³/₂) (¹⁸/₂) = ⁵⁴/₈ = 6³/₄


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