Answer :

D1eformetal
[tex]- \frac{9}{16}= -\frac{45}{80} \\ \\ -\frac{3}{5} = -\frac{48}{80} \\ \\ -\frac{45}{80} >- \frac{48}{80} \\ \\ =>- \frac{9}{16} > -\frac{3}{5} \\ \\ \framebox[1.1\width]{See u :)} \par[/tex]

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