Answer :

[tex]4 x^{2} -y^{2} -6y-9 \\ 4 x^{2} = y^{2} +6y+9 \\ 4 x^{2} =(y+3)(y+3) \\ \sqrt{ 4x^{2} } = \sqrt{(y+3)(y+3)} =\\2x=y+3\\2x-3=y[/tex]

y=2x-3
=4x²-(y²+6y+9)
=(2x)²-(y+3)²
=(2x+y+3)*(2x-y-3)

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