Answer :
you will have to complete the square
factor the 4 out of the first two terms
y = 4(x^2 - 2x) + 5
x^2 - 2x + 1 = (x - 1)^2
we want what we have to look like this
the difference between (x^2 - 2x) and (x^2 - 2x + 1) is the +1
so we add a 1 and subtract a 1 to keep balance
y = 4(x^2 - 2x + 1 -1) + 5
y = 4(x^2 - 2x + 1) - 4 + 5 [moved the extra -1 out of it and distributive property]
y = 4(x - 1)^2 + 1 [factored and added like terms]
y = 4(x-1)^2 + 1
or
y - 1 = 4(x-1)^2
is now in vertex form.
factor the 4 out of the first two terms
y = 4(x^2 - 2x) + 5
x^2 - 2x + 1 = (x - 1)^2
we want what we have to look like this
the difference between (x^2 - 2x) and (x^2 - 2x + 1) is the +1
so we add a 1 and subtract a 1 to keep balance
y = 4(x^2 - 2x + 1 -1) + 5
y = 4(x^2 - 2x + 1) - 4 + 5 [moved the extra -1 out of it and distributive property]
y = 4(x - 1)^2 + 1 [factored and added like terms]
y = 4(x-1)^2 + 1
or
y - 1 = 4(x-1)^2
is now in vertex form.
a=4, b=-8, c=5
h=-b/2a= -(-8)/2(4)
8/8=h=1
K= a(h)^2+b(h)+c
K= 4(1)^2-8(1)+5
K= 4-8+5
K= 1, Vertex Form: a(x-h)^2+k
Vertex Form: Y= 4(X-(1)^2+K
Y= 4(x-1)^2+1
