part: 1
The width of a rectangle is 13 its length, l.

Which expression represents the perimeter of the rectangle?

1/3 L+L

2(L+1/3L)

4×1/3L

4(l+1/3L)

Part 2

The perimeter of the rectangle from Part 1 is 56 inches.

What is the area of the rectangle, in square inches?

____________________square inches

Question

14-03-2015
Mathematics

Answered

part: 1
The width of a rectangle is 13 its length, l.

Which expression represents the perimeter of the rectangle?

1/3 L+L

2(L+1/3L)

4×1/3L

4(l+1/3L)

Part 2

The perimeter of the rectangle from Part 1 is 56 inches.

What is the area of the rectangle, in square inches?

____________________square inches

Answer :

Other Questions

Which statement best describes the media's role in informing the public on government affairs?A. The media presents information, allowing the public to stay inf

What is the primary environmental concern associated with emissions from combustion engines?a) Noise pollutionb) Thermal pollutionc) Air pollutiond) Light pollu

Given [tex]\[ \left[\begin{array}{cc}12 & -13 \\ 17 & -22\end{array}\right]\left[\begin{array}{l}x \\ y\end{array}\right]=\left[\begin{array}{c}7 \\ -51

Given the text's context, it appears that it refers to an excerpt where the place where more elephants are bred is discussed. However, it contains several unnec

What are the solutions of the equation [tex]$x^4+6x^2+5=0$[/tex]? Use [tex]$u$[/tex] substitution to solve.A. [tex]x = i[/tex] and [tex]x = i \sqrt{5}[/tex]B. [

Which of the following is an example of potential energy?A. burning woodB. chewing foodC. riding an exercise bikeD. water stored in a reservoirE. a fan blade tu

Kevin has an upcoming IEP meeting; however, the school is having a difficult time convincing his parents to attend the meeting. What is the recommended action t

Find the asymptotes of the curve [tex]y = \sqrt{1+x^2} \sin \frac{1}{x}[/tex].

Find the polar coordinates [tex]$(r, \theta)$[/tex], where [tex]$\theta$[/tex] is in degrees, for the rectangular coordinates [tex]$(2, -2)$[/tex].A. [tex

Select the factors that are part of the polynomial [tex]-12x^5 + 15x^3 + 18x[/tex].A. [tex]x^2 - 2[/tex]B. [tex]x + 1[/tex]C. [tex]x - 1[/tex]D. [tex]x^2[/tex]E

anijlin anijlin · Answer 1 · 2015-03-14T21:38:14-04:00

Part 1:
perimeter = 2(Length + width)
if the width is 1/3 it's length, then
width = 1/3L
plug that into the first equation
perimeter = 2( L + 1/3L)

Part 2:
the perimeter of the rectangle from part 1 is 56 inches. using this we can solve for L, the length:
56 = 2(L + 1/3 L)
56 = 2L + 2/3L
56 = 2 2/3 L
L = 21

Now that we know the length, we can solve for the width.
L = 21
W = 1/3 L
W = 1/3 x 21
W = 7

Using the Length (21 inches) and the Width (7 inches), we can solve for the area of the rectangle.
Area = length x width
Area = 21 inches x 7 inches
Area = 147 square inches