Answer :
[tex]D:3x>0 \wedge x-4>0\\
D:x>0 \wedge x>4\\
D:x>4\\\\
\log_63x+\log_6(x-4)=2\\
\log_63x(x-4)=\log_636\\
3x(x-4)=36\\
3x^2-12x=36\\
3x^2-12x-36=0\\
x^2-4x-12=0\\
x^2+2x-6x-12=0\\
x(x+2)-6(x+2)=0\\
(x-6)(x+2)=0\\
x=6 \vee x=-2\\
-2\not \in D \Rightarrow x=6[/tex]
