Answer :
[tex] \frac{4}{5}- \frac{3}{10}= \frac{4\cdot2}{5\cdot2}- \frac{3}{10}= \frac{8}{10}- \frac{3}{10}=\boxed{\boxed{ \frac{5}{10} }}=\boxed{\boxed{\boxd{\boxed{\frac{1}{2}}}}} [/tex]
[tex] \frac{4}{5} - \frac{3}{10} \\
\\ \frac{4*2}{5*2}= \frac{8}{10} \\
\\ \frac{3*1}{10*1}= \frac{3}{10} \\
\\ \frac{8}{10} - \frac{3}{10}= \frac{5}{10} \\
\\ \frac{5:5}{10:5}= \frac{1}{2} \\
\\ Solution: \frac{1}{2} \\ [/tex]