Answer :
n^2+2n-48
(n+8) (n-6)
explanation
-48 tells me the signs of the numbers are different and that I must subtract
two numbers multiplied = 48 subtracted = +2
+8. and -6
[tex]n^2+2n-48=n^2+8n-6n-48\\\\=n\cdot n+n\cdot8-6\cdot n-6\cdot8\\\\=n(n+8)-6(n+8)\\\\=\boxed{(n+8)(n-6)}[/tex]