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A parallelogram with an equal base and height and an area greater than 64 square meters



Answer :

Greenleafable
" Draw and then find the area" the base is equal to the height, and the area formula is A=BxH, so A=B²=H², if A>64m², so H>8 or B>8 (when drawing the figure)
calculista

Answer:

The base and the height of the parallelogram must be greater than [tex]8\ meters[/tex]

Step-by-step explanation:

we know that

The area of a parallelogram is equal to

[tex]A=bh[/tex]

where

b is the base

h is the height

In this problem we have

[tex]b=h[/tex] -----> given problem

so

[tex]A=b^{2}[/tex] ----> equation A

[tex]A> 64\ m^{2}[/tex] ------> inequality B

substitute equation A in the inequality B

[tex]b^{2}> 64\ m^{2}[/tex]

[tex]b> 8\ m[/tex]

The base and the height of the parallelogram must be greater than [tex]8\ meters[/tex]


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