Answer :
" Draw and then find the area" the base is equal to the height, and the area formula is A=BxH, so A=B²=H², if A>64m², so H>8 or B>8 (when drawing the figure)
Answer:
The base and the height of the parallelogram must be greater than [tex]8\ meters[/tex]
Step-by-step explanation:
we know that
The area of a parallelogram is equal to
[tex]A=bh[/tex]
where
b is the base
h is the height
In this problem we have
[tex]b=h[/tex] -----> given problem
so
[tex]A=b^{2}[/tex] ----> equation A
[tex]A> 64\ m^{2}[/tex] ------> inequality B
substitute equation A in the inequality B
[tex]b^{2}> 64\ m^{2}[/tex]
[tex]b> 8\ m[/tex]
The base and the height of the parallelogram must be greater than [tex]8\ meters[/tex]
