Answer :
[tex]h(t)=-5t^2+25\\-5t^2+25=0\\25=5t^2\\5=t^2\\\sqrt{5}=t\\\\A(t)=\frac{f(t+h)-f(t)}{h}\\A(0)=\frac{f(\sqrt{5})-f(0)}{\sqrt{5}}\\A(0)=\frac{0+25}{\sqrt{5}}\\A(0)=\frac{25\sqrt{5}}{5}\\A(0)=5\sqrt{5}\\\\h'(t)=-10t\\h'(\sqrt{5})=-10(\sqrt{5})[/tex]
A. sqrt(5)
B. 5 sqrt(5)
C. 10 sqrt(5)
A. sqrt(5)
B. 5 sqrt(5)
C. 10 sqrt(5)