Answer :
2x2+2x[tex] \sqrt{(2/2) x^{2} +3 x^{2} } +2 x \sqrt{(2/2) x^{2} +3 x^{2} }[/tex]
The answer is about 16.649
The answer is about 16.649
Answer:
Lateral area of a regular pyramid with square is 12.64 square unit
Step-by-step explanation:
Given : A regular pyramid with base is a square.
We have to find the lateral area for the regular pyramid.
Lateral area of a regular pyramid with square = [tex]a\sqrt{a^2+4h^2}[/tex]
Where, a is side of square
and h is height of pyramid.
Substitute, a = 2
and h = 3
we have,
Lateral area of a regular pyramid with square = [tex]2\sqrt{(2)^2+4(3)^2}[/tex]
Simplify, we have,
Lateral area of a regular pyramid with square = 12.64
Thus, The Lateral area of a regular pyramid with square is 12.64 square unit
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Question
Find the lateral area for the regular pyramid.