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Balanced Rock has a mass of about 36,000 kg. If the acceleration due to gravity is 9.8 m/s², (9.8 squared) what is the force that the rock is exerting on its pedestal? Include labels.

HINT: Remember Newton's second law, F=MA.



Answer :

That means the rock has a downward force due to gravity of 
(9.8)(36,000) = 352,800 N downwards on a free body diagram. If the rock is balanced, that means the normal force up is equal to 352,800 N. And due to Newton's about equal and opposite reactions, if the pedestal is pushing up on the rock with 352,800 N of force, then the rock is exerting 352,800 N of force onto the pedestal. 
SchwarzschildRadius
So,

Newton's Second Law says: force = mass * acceleration

Plug in the given values.
force = 36,000 kg * 9.8 m/s^2
[tex]force = 352,800 \frac{kg * m}{ s^{2} } [/tex]

force = 352,800 Newtons to the (direction)

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