Count by fourths from 0 to 4.

The skip count from 0 to 4 is [tex]0,\frac{1}{4} ,\frac{2}{4} ,\frac{3}{4} ,\frac{4}{4}=1 ,\frac{5}{4} ,\frac{6}{4} ,\frac{7}{4} \frac{8}{4}=2 ,\frac{9}{4} ,\frac{10}{4} ,\frac{11}{4} ,\frac{12}{4} = 3,\frac{13}{4},\frac{14}{4} ,\frac{15}{4} ,\frac{16}{4}=4[/tex]

What is skip counting?

Skip counting is a method of counting numbers by adding every time to the previous number.

According to the given question

We have to count by fourths from 0 to 4.

Here, we add the number [tex]\frac{1}{4}[/tex] for each counting, in such manner that the counting is represented in alternate numbers.

Therefore,

the skip count by fourth from 0 to 4 are

[tex]0,\frac{1}{4} , \frac{2}{4} ,\frac{3}{4} ,\frac{4}{4} =1,\frac{5}{4} ,\frac{6}{4} ,\frac{7}{4} ,\frac{8}{4},\frac{9}{4} ,\frac{10}{4},\frac{11}{4} ,\frac{12}{4} ,\frac{13}{4},\frac{15}{4} ,\frac{16}{4} =4[/tex]

Learn more about skip counting here:https://brainly.com/question/21555185

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