In water, the greater the depth, the higher the pressure.
For every 10 m increase in depth, water pressure
increases by about 100 kilopascals (kPa). At a depth of
40 , the pressure is approximately 500 kPa.
/1 a. State the independent and dependent variables in this
scenario.
Answer:
/1 b. What is the rate of change in this relationship?
c. Write the equation of a linear relation representing the pressure, p, at a depth, d, under water.

Answer:

40m deep = 500 kPa.
+10m deep = +100 kPa
50m deep = 600 kPa
60m deep = 700 kPa
and so on.

a. The depth affects the water pressure, not the other way around, and thus the depth is the independant variable and the water pressure is the dependant variable.

b. 100 kPa every 10 meters, or 10 kPa per meter.

c. 0m deep = 100 kPa. Add 10 kPa for every meter.
kPa = 100 + (10 times the depth in meters)
Using the variables given, p = 10d + 100.

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