vafamily
vafamily
31-03-2015
Mathematics
Answered
how do i solve 2x^2+5x+2=9
Answer :
Panoyin
Panoyin
31-03-2015
2x² + 5x + 2 = 9
2x² + 5x + 2 - 9 = 9 - 9
2x² + 5x - 7 = 0
x =
-5 +/- √(5² - 4(2)(-7))
2(2)
x =
-5 +/- √(25 + 56)
4
x =
-5 +/- √(81)
4
x =
-5 +/- 9
4
x =
-5 + 9
x =
-5 - 9
4 4
x =
4
x =
-14
4 4
x = 1 x = -3.5
Answer Link
konrad509
konrad509
01-04-2015
[tex]2x^2+5x+2=9\\ 2x^2+5x-7=0\\ 2x^2-2x+7x-7=0\\ 2x(x-1)+7(x-1)=0\\ (2x+7)(x-1)=0\\ x=-\dfrac{7}{2} \vee x=1[/tex]
Answer Link
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