Answer :
[tex]v^2+4v-22=10 \\
v^2+4v+4-4-22=10 \\
(v+2)^2-26=10 \\
(v+2)^2=36 \\
\sqrt{(v+2)^2}=\sqrt{36} \\
|v+2|=6 \\
v+2=6 \ \lor \ v+2=-6 \\
v=4 \ \lor \ v=-8 \\
\boxed{v=-8 \hbox{ or } v=4}[/tex]
v² + 4v - 22 = 10
- 10 - 10
v² + 4v - 32 = 0
v = -4 +/- √(4² - 4(1)(-32))
2(1)
v = -4 +/- √(16 + 128)
2
v = -4 +/- √(144)
2
v = -4 +/- 12
2
v = -2 +/- 6
v = -2 + 6 ∨ v = -2 - 6
v = 4 ∨ v = -8
- 10 - 10
v² + 4v - 32 = 0
v = -4 +/- √(4² - 4(1)(-32))
2(1)
v = -4 +/- √(16 + 128)
2
v = -4 +/- √(144)
2
v = -4 +/- 12
2
v = -2 +/- 6
v = -2 + 6 ∨ v = -2 - 6
v = 4 ∨ v = -8