Answer :
2/3 = x/(3x + y)
Cross multiply:
3x = 2(3x + y)
Distribute 2:
3x = 6x + 2y
Subtract 6x to both sides:
-3x = 2y
Divide 'y' to both sides:
-3x/y = 2
Divide -3 to both sides:
x/y = -2/3
Cross multiply:
3x = 2(3x + y)
Distribute 2:
3x = 6x + 2y
Subtract 6x to both sides:
-3x = 2y
Divide 'y' to both sides:
-3x/y = 2
Divide -3 to both sides:
x/y = -2/3
2/3 = x/3x + y
2(3x + y) = 3x
2(3x) + 2(y) = 3x
6x + 2y = 3x
- 6x - 6x
2y = -3x
2 2
y = -1.5x
2(3x + y) = 3x
2(3x) + 2(y) = 3x
6x + 2y = 3x
- 6x - 6x
2y = -3x
2 2
y = -1.5x