Answer :
[tex]x+y=3 \ \ \ |\times (-1) \\
2x+y=5 \\ \\
-x-y=-3 \\
\underline{2x+y=5 \ \ \ \ } \\
2x-x=5-3 \\
x=2 \\ \\
x+y=3 \\
2+y=3 \\
y=3-2 \\
y=1 \\ \\
\hbox{the point of intersection - } (x,y)=(2,1)
[/tex]
1x + 1y = 3 ⇒ 2x + 2y = 6
2x + 1y = 5 ⇒ 2x + 1y = 5
y = 1
2x + 1 = 5
- 1 - 1
2x = 4
2 2
x = 2
(x, y) = (2, 1)
2x + 1y = 5 ⇒ 2x + 1y = 5
y = 1
2x + 1 = 5
- 1 - 1
2x = 4
2 2
x = 2
(x, y) = (2, 1)