one-third of the fish in Liam's fish tank were added today. Half of the other fish were a gift to Liam last week. the other 9 came from Liam's old fish tank. How many fish are in the tank? What is the difference between the number of fish Liam had in his old tank and the number he has now?

There are 54 fish in the tank. The difference between the fish he had and the fish he has now is 45 fish. 1/3=2/6 1/2=3/6. I converted so there is a common denominator. 2/6+3/6=5/6. That leaves 9 fish. 9 fish is 1/6. So if I multiply 9 by 5 that gives me the rest of the fish, which is 45. Then, I add that together to get 54.

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aachen aachen · Answer 2 · 2019-09-21T16:50:50-04:00

Answer: Total fish are 27, difference is 18

Step-by-step explanation:

Given: one-third of the fish in Liam's fish tank were added today. Half of the other fish were a gift to Liam last week. the other 9 came from Liam's old fish tank.

To Find: Number of the fish in the tank, difference between the number of fish Liam had in his old tank and the number he has now.

Solution: Let the total fish in tank be = x

total fish added today = [tex]\frac{1}{3}\times \text{x}[/tex]

Total fish left = [tex]\text{x}-\frac{1}{3}\text{x}[/tex]= [tex]\frac{2}{3}\text{x}[/tex]

Fish gifted to him last week = [tex]\frac{1}{2}\times\frac{2}{3}\times \text{x}[/tex]

= [tex]\frac{1}{3}\text{x}[/tex]

Fish left = [tex]\frac{2}{3}\text{x}[/tex] - [tex]\frac{1}{3}\text{x}[/tex]

[tex]\frac{1}{3}\text{x}[/tex]

now,

fish left in the tank are =[tex]\frac{1}{3}\text{x}[/tex]

fish from liam's old tank = 9 = fish left in the tank

[tex]\frac{1}{3}\text{x}[/tex] = 9

[tex]\text{x}[/tex]=[tex]27[/tex]

Total fish in liam's new tank= [tex]27[/tex]

difference between the number of fish Liam had in his old tank and the number he has now

= [tex]27-9=18[/tex]

Total Fish in Liam's new tank are 27 and difference between the number of fish Liam had in his old tank and the number he has now is 18.