Answer :

0000000
[tex]^{16)}8-1\frac{11}{16}= \frac{128}{16}- \frac{1\cdot16+11}{16}= \frac{128-27}{16}=\bold{ \frac{101}{16}} \\ \\ 1 \frac{3}{5}+1 \frac{1}{4}=^{4)}\frac{1\cdot5+3}{5} +^{5)}\frac{1\cdot4+1}{4}= \frac{32}{20}+ \frac{25}{20}=\bold{ \frac{57}{20}} \\ \\ 5 \frac{1}{4}-1 \frac{1}{8}=^{4)}\frac{5\cdot4+1}{4} -^{2)}\frac{1\cdot8+1}{8}= \frac{84}{16}- \frac{18}{16}= \frac{66}{16}^{(2}=\bold{ \frac{33}{8} } [/tex]
Hippalectryon
[tex]\frac{8}1-1\frac{11}{16}=(8-1)-\frac{11}{16}=6\frac{16-11}{16}=\boxed{6\frac{5}{16}}[/tex]

[tex]1\frac{3}5+1\frac{1}4=(1+1)+\frac{3}5+\frac{1}4=2+\frac{3\cdot4+5}{4\cdot5}=\boxed{2\frac{17}{20}}[/tex]

[tex]5\frac{1}4-1\frac{1}8=(5-1)+(\frac{1}4-\frac{1}8)=4+\frac{2-1}{8}=\boxed{4\frac{1}8}[/tex]

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