Answer :

[tex]4\frac{2}{7}\cdot2\frac{1}{5}=\frac{4\cdot7+2}{7}\cdot\frac{2\cdot5+1}{5}=\frac{30}{7}\cdot\frac{11}{5}=\frac{30:5}{7}\cdot\frac{11}{5:5}=\frac{6}{7}\cdot\frac{11}{1}\\\\=\frac{6\cdot11}{7\cdot1}=\frac{66}{7}=\boxed{9\frac{3}{7}}[/tex]