Answer :
3n=3u+p
n=3u+p/3
dont read under here ....
uhdusbsacucuabcuabcjaSCC
CS s
c
sc sc scacac adc dch dv uvb
sasc dv d dac d d d
c cs cas
n=3u+p/3
dont read under here ....
uhdusbsacucuabcuabcjaSCC
CS s
c
sc sc scacac adc dch dv uvb
sasc dv d dac d d d
c cs cas
[tex]p=3n+3u\\\\3n+3u=p\ \ \ /-3u\\\\3n+3u-3u=p-3u\\\\3n=p-3u\ \ \ /:3\\\\3n:3=(p-3u):3\\\\n=\frac{p-3u}{3}\to n=\frac{p}{3}-\frac{3u}{3}\to n=\frac{1}{3}p-u[/tex]