Answer :
[tex]\begin{array}{lll}(2x^3 + 4x^2 +15x-8):(x-3) = 2x^2+10x +45\\
\underline{-2x^3 + 6x^2} & & \\\qquad\ \ 10x^2+15x-8 & & \\\qquad \ \ \underline{-10x^2+30x} & &\\
\qquad \qquad \qquad 45x-8 & & \\
\qquad \qquad \quad \underline{-45x + 135} & & \\
\qquad \qquad \qquad R=127& & \\\end{array}\\\\(2x^3+4x^2+15x-8):(x-3)=2x^2+10x+45+\frac{127}{x-3}\\\\[/tex]